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1 Applied Design Loads (ULS)
Design values at Ultimate Limit State (ULS). Include load combination factors γF ·ψ per EN 1990 before entry.
2 Element Dimensions — Rectangular Cross-section
Dimensions
h =
mm
depth (strong axis)
b =
mm
width (weak axis)
Section Properties
A = b · h =
30000 mm²
Iy = b·h³/12 =
100.00 ×10⁶ mm⁴
Iz = b³·h/12 =
56.25 ×10⁶ mm⁴
3 Material Properties — C14
Timber Strength Class (EN 338)
Class:
C14
C16
C18
C20
C22
C24
C27
C30
C35
C40
C45
C50
D18
D24
D30
D35
D40
D50
D60
D70
fm,k =
N/mm²
char. bending strength
ρwood =
350
kg/m³
mean density (EN 338)
Modification Factors
γM =
EN 1995-1-1 Table 2.3
kmod =
EN 1995-1-1 Table 3.1
kh =
1.000
EN 1995-1-1 §3.2(3)
kh = min((150/h)0.2 , 1.3) when h < 150 mm and ρ < 700 kg/m³; else kh = 1.0
EN 338 Class Properties (N/mm²)
Class fm,k ft,0,k
fc,0,k fv,k
E0,mean kN/mm²
ρmean kg/m³
4 Design Bending Strength
Per EN 1995-1-1 §2.4.1, Eq. (2.14): fm,d = kmod · kh · fm,k / γM
fm,y,d = fm,z,d
= kmod · kh · fm,k / γM =
8.62
N/mm²
(same value for both axes — rectangular section)
5 Design Bending Stresses
σm,y,d
= My,Ed · (h/2) / Iy =
4.00
N/mm²
Design bending stress about the principal y-y axis (EN 1995-1-1 §6.1.6)
σm,z,d
= Mz,Ed · (b/2) / Iz =
0.67
N/mm²
Design bending stress about the principal z-z axis (EN 1995-1-1 §6.1.6)
km
= 0.7 for rectangular sections
EN 1995-1-1 §6.1.6(2)
6 Biaxial Bending Verification — EN 1995-1-1 §6.1.6
Check 1 — Strong axis (y-y) governs — Eq. (6.11)
(σm,y,d /fm,y,d ) + km ·(σm,z,d /fm,z,d ) =
0.518
≤ 1.00
OK
Eq. (6.11)
Check 2 — Weak axis (z-z) governs — Eq. (6.12)
km ·(σm,y,d /fm,y,d ) + (σm,z,d /fm,z,d ) =
0.402
≤ 1.00
OK
Eq. (6.12)
Governing utilization ratio
0.518
Element status
✓ ADEQUATE
References: EN 1995-1-1:2004 — Eurocode 5: Design of timber structures — Part 1-1: Common rules and rules for buildings |
EN 338:2003 — Structural timber; Strength classes